Five friends P, Q. R. S and T are compared on the basis of their height (not necessarily in the same order). Height of T is between P and Q. T is taller than S. R’s height is more than P and T. Which of the following sequence of their height cannot be possible?
I. R > P > T > Q > S
II. R > S > Q > T > P
III. Q > R > T > S > P

Correct option is A

Given Information:
· T's height is between P and Q.
· T is taller than S.
· R is taller than both P and T.
Analyze the sequences:
Sequence I:R > P > T > Q > S
· T is taller than S (which is correct: T > S).
· T's height is between P and Q (this is also correct in this sequence, as T is between P and Q).
· R is taller than P and T, which is correct (R > P > T).
· Thus, this sequence is possible.
Sequence II: R > S > Q > T > P
· T is taller than S (this is not correct here, because in this sequence, T is shorter than S: S > T).
· Since this violates the condition that T is taller than S, this sequence cannot be possible.
Sequence III: Q > R > T > S > P
· T is taller than S (this is correct: T > S).
· T's height is between P and Q (this is not correct in this sequence, as T is not between P and Q, but rather between R and S).
· Thus, this sequence cannot be possible.
Conclusion:
The only sequence that cannot be possible is Sequence II.