Find the value of k if 13-[10-{16+8÷(k-2)}+2]=20.

​13-[10-{16+8÷(k-2)}+2]=20 

Simplification using BODMAS rule;

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​

​Solution:

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