Correct option is BGiven:[(95)−6×(59)−4×(13)−2]−2\left[ \left(\frac{9}{5}\right)^{-6} \times \left(\frac{5}{9}\right)^{-4} \times \left(\frac{1}{3}\right)^{-2} \right]^{-2}[(59)−6×(95)−4×(31)−2]−2Formula Used:a-n = (1a)n\left(\frac 1a\right)^n(a1)n Solution:[(95)−6×(95)4×(13)−2]−2\left[ \left(\frac{9}{5}\right)^{-6} \times \left(\frac95\right)^{4} \times \left(\frac{1}{3}\right)^{-2} \right]^{-2}[(59)−6×(59)4×(31)−2]−2=[(95)−6+4×(13)−2]−2\left[ \left(\frac{9}{5}\right)^{-6+4} \times \left(\frac{1}{3}\right)^{-2} \right]^{-2}[(59)−6+4×(31)−2]−2=[(95)−2×(13)−2]−2\left[ \left(\frac{9}{5}\right)^{-2} \times \left(\frac{1}{3}\right)^{-2} \right]^{-2}[(59)−2×(31)−2]−2= [(95×13)−2]−2\left[ \left(\frac{9}{5}\times\frac{1}{3}\right)^{-2} \right]^{-2}[(59×31)−2]−2=[(35)−2]−2\left[ \left(\frac{3}{5}\right)^{-2} \right]^{-2}[(53)−2]−2 =(35)−2×−2\left( \frac35 \right) ^{ -2 \times -2}(53)−2×−2 = (35)4\left( \frac{3}{5}\right)^4(53)4