Find the value of [(49÷7)×{$$\frac {57}3$$​+$$\frac {19}7$$​×(9-2)}]

Correct option is B

Given:
 [(49÷7)×{$$\frac {57}3$$​​+$$\frac {19}7$$​×(9-2)}] 
Solution:
[(49÷7)×{$$\frac {57}3$$​​+$$\frac {19}7$$​×(9-2)}]|

= [7 ×{$$\frac {57}3$$​​​+$$\frac {19}7$$​×7}]|

= 7 ×{19 + 19}
= 7 × 38 
= 266