Find the value of $$40^{-7} ÷ (40^{19}× 40^4)$$

Correct option is C

Given:
​$$40^{-7} \div (40^{19} \times 40^{4}) \\$$ 
Formula Used:
​$$a^m \div a^n = a^{m-n} \\a^m \times a^n = a^{m+n} \\$$ 
Solution:
​$$40^{-7} \div (40^{19} \times 40^4) \\\Rightarrow 40^{-7} \div 40^{(19+4)} \\\Rightarrow 40^{-7} \div 40^{23} \\\Rightarrow 40^{-7 - 23} = 40^{-30} \\\therefore 40^{-7} \div (40^{19} \times 40^4) = 40^{-30}$$​​