Find the value of $$4^{-5}÷4^7×4^{-6}$$ ​

Correct option is A

Given:

​$$4^{-5}÷4^7×4^{-6}$$ =?​

Concept Used:

The division rule for exponents states:

​$$\frac{a ^m}{a ^n} ​ =a ^{m−n}$$ 

Using the multiplication rule for exponents:

​$$a ^m ×a ^n =a ^{m+n}$$​​

Solution: 

​$$4^{-5}÷4^7×4^{-6}$$ 

$$4^{-5} \div 4^7 \times 4^{-6} \\ \ \\ = 4^{-5-7} \times 4^{-6} \\ \ \\= 4^{-12} \times 4^{-6}\\ \ \\ = 4^{-12+(-6)}\\ \ \\ = 4^{-18}$$ 

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