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Find the value of [(35÷5)×{126+252×(9−7)}][(35\div5) × \{\frac{12}{6}+\frac{25}{2} × (9-7)\}][(35÷5)×{612​+225​×(9−7)}]​​
Question

Find the value of [(35÷5)×{126+252×(97)}][(35\div5) × \{\frac{12}{6}+\frac{25}{2} × (9-7)\}]​​

A.

170

B.

172

C.

174

D.

189

Correct option is D

Given:

[(355)×{126+252×(97)}]\left[ \left( \frac{35}{5} \right) \times \left\{ \frac{12}{6} + \frac{25}{2} \times (9 - 7) \right\} \right] 

Concept Used:

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}  

Solution: 

[(355)×{126+252×(97)}]\left[ \left( \frac{35}{5} \right) \times \left\{ \frac{12}{6} + \frac{25}{2}\times (9 - 7) \right\} \right] 

=[(7)×{126+252×(2)}]=\left[ \left( 7 \right) \times \left\{ \frac{12}{6} + \frac{25}{2} \times (2) \right\} \right] 

=[(7)×{2+252×(2)}]=\left[ \left( 7 \right) \times \left\{ 2 + \frac{25}{2}\times (2) \right\} \right] 

=[(7)×{2+25}]=\left[ ( 7 ) \times \{2 + 25\} \right] 

(7×27) ( 7 \times 27 ) 

= 189

Thus the solution is 189.



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