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Find the value of [(32÷8)×{155+305×(7−2)}][(32\div8) × \{\frac{15}{5}+\frac{30}{5} × (7-2)\}][(32÷8)×{515​+530​×(7−2)}]​​
Question

Find the value of [(32÷8)×{155+305×(72)}][(32\div8) × \{\frac{15}{5}+\frac{30}{5} × (7-2)\}]​​

A.

116

B.

132

C.

149

D.

143

Correct option is B

Given:

[(328)×{155+305×(72)}]\left[ \left( \frac{32}{8} \right) \times \left\{ \frac{15}{5} + \frac{30}{5} \times (7 - 2) \right\} \right]​​

Concept Used:

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}  

Solution:

=[(328)×{155+305×(72)}]\left[ \left( \frac{32}{8} \right) \times \left\{ \frac{15}{5} + \frac{30}{5} \times (7 - 2) \right\} \right] 

=[(4)×{3+305×(5)}]=\left[ \left( 4 \right) \times \left\{ 3 + \frac{30}{5} \times (5) \right\} \right] 

=[(4)×{3+30}]=\left[ \left( 4 \right) \times \left\{ 3 + {30} \right\} \right] 

=[4× 33]=\left[ 4\times \ 33 \right] 

= 132 


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