Correct option is A
Given:
[(30÷5)×{630+119×(4−3)}]
Concept Used:
Operation preference wiseBracketsOrders, ofDivisionMultiplicationAdditionSubtractionSymbol[],,()x(power),√(root),of÷×+−
Solution:
[(30÷5)×{630+119×(4−3)}]
= [6×{630+119×(4−3)}]
= [6×{630+119×1}]
=6×{630+119×1}]
= 6×630+114
= 6×6144=144
Option (A) is right.