Find the value of [290 ÷ {17 + 7 × (2 − 3)}].

Correct option is D

Given:

​[290 ÷ {17 + 7 × (2 − 3)}].

Concept Used:

​$$\begin{array}{|l|l|}\hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} & [\,], \{\,\}, (\,) \\\hline\text{Orders, of} & ^x \, (\text{power}), \, \sqrt{} \, (\text{root}), \, \text{of} \\\hline\text{Division} & \div \\\hline\text{Multiplication} & \times \\\hline\text{Addition} & + \\\hline\text{Subtraction} & - \\\hline\end{array}$$

Solution:

[290 ÷ {17 + 7 × (-1)}]

= [290 ÷ {17 -7}]

= [290 ÷ 10] = 29