Find the value of $$(22+8\sqrt{\smash[b]{6}})^{1/2}$$.​​

Correct option is D

Given:

​$$(22+8\sqrt{\smash[b]{6}})^{1/2}$$​. 

Formula Used:  

$$(a+b)^2 = a^2 + b^2 + 2ab$$  

Solution:

​$$(22+8\sqrt{\smash[b]{6}})^{1/2}$$​

=   $$((4)^2 + (\sqrt6)^2 +2 \times 4\sqrt{\smash[b]{6}})^{1/2}$$​.    

= $$[( 4 + \sqrt6)^2]^{1/2}$$ 

= 4 + $$\sqrt6$$​​