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Find the value of [(21÷7)×639+142×(4−2)][(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}][(21÷7)×963​+214​×(4−2)]​​
Question

Find the value of [(21÷7)×639+142×(42)][(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}]​​

A.

48

B.

35

C.

65

D.

73

Correct option is B

Given:
[(21÷7)×639+142×(42)][(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}] \\​​
Concept Used: 

Simplification based on BODMAS rule;
Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}

Solution:

[(21÷7)×639+142×(42)]=[3×7+7×2]=[3×7+14]=[21+14]=35[(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}] \\= [3 ×{7 + 7 × 2}]\\= [3 ×{7 + 14}]\\= [21 + 14 ]\\= 35​​

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