Find the value of [(21÷7)×639+142×(4−2)][(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}][(21÷7)×963+214×(4−2)]

Correct option is B

Given:
$[(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}] \\$
Concept Used:

Simplification based on BODMAS rule;

\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}

Solution:

$[(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}] \\= [3 ×{7 + 7 × 2}]\\= [3 ×{7 + 14}]\\= [21 + 14 ]\\= 35$

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Find the value of $[(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}]$

48

35

65

73

Correct option is B

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Find the value of [(21÷7)×639+142×(4−2)][(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}][(21÷7)×963​+214​×(4−2)]​​

48

35

65

73

Correct option is B

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SSC CGL T-I Similar Paper (Held on 12 Sep 2025 S2)

SSC CGL T-I GA Section Test 01

SSC CGL T-I Full Mock Test 1 (Exam Level)

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Access ‘SSC GD’ Mock Tests with

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Find the value of $[(21÷7)×{\frac{63}{9} + \frac{14}{2} ×(4-2)}]$