​$$\text{Find the value of } \left(\frac{1}{4}\right)^{-2} + \left(\frac{1}{9}\right)^{-2} + \left(\frac{1}{3}\right)^{-2}.$$​​

Correct option is B

Given:

​$$\left(\frac{1}{4}\right)^{-2} + \left(\frac{1}{9}\right)^{-2} + \left(\frac{1}{3}\right)^{-2}.$$

Formula Used:

a^-n = $$\left(\frac 1a\right)^n$$

Solution:

​$$\left(\frac{1}{4}\right)^{-2} + \left(\frac{1}{9}\right)^{-2} + \left(\frac{1}{3}\right)^{-2}.$$

= 4² + 9² + 3²​

= 16 + 81 + 9 = 106