Find the value of $$\left( \frac{1}{4} \right)^{-2} + \left( \frac{1}{8} \right)^{-2} + \left( \frac{1}{5} \right)^{-2}$$​​

Correct option is A

Given:

​$$\left( \frac{1}{4} \right)^{-2} + \left( \frac{1}{8} \right)^{-2} + \left( \frac{1}{5} \right)^{-2}$$​​

Concept Used:

​$$\left( \frac{1}{a} \right)^{-n} = a^n$$ 

Solution: ​

​$$\left( \frac{1}{4} \right)^{-2} + \left( \frac{1}{8} \right)^{-2} + \left( \frac{1}{5} \right)^{-2} \\ \ \\ = \left( {4} \right)^{2} + \left({8} \right)^{2} + \left({5} \right)^{2}\\ \ \\ = 16 +64+25 \\ \ \\ = 105$$​​