Find the value of $$\left(\frac{1}{3}\right)^{-4} + \left(\frac{1}{6}\right)^{-4} + \left(\frac{1}{8}\right)^{-4}.$$​​

Correct option is C

Given:
​$$\left(\frac{1}{3}\right)^{-4} + \left(\frac{1}{6}\right)^{-4} + \left(\frac{1}{8}\right)^{-4}.$$
Solution:
​$$\left(\frac{1}{3}\right)^{-4} + \left(\frac{1}{6}\right)^{-4} + \left(\frac{1}{8}\right)^{-4} \\= 3^4 + 6^4 + 8^4\\= 81 + 1296 + 4096\\= 5473$$​​