Find the value of $$\frac{119.5^2-116.4^2}{119.5-116.4}$$.​

Correct option is D

Given:

​$$\frac{119.5^2-116.4^2}{119.5-116.4}$$ 

Formula used:

​$$a^2-b^2= (a+b)(a-b)$$

Solution:

Here,

​$$a$$ = 119.5 , $$b$$ = 116.4

So, 

​$$\frac{a^2-b^2}{a-b}$$

= $$\frac{(a+b)(a-b)}{a-b}$$ = ($$a+b$$)

Now, Substitute the value of $$a$$ and $$b$$ 

= ($$a+b$$)

= 119.5+116.4

= 235.9

Thus the correct answer is (D)

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