Find the value of $$\tfrac{1}{1+\tfrac{1}{3}}-\tfrac{1}{1+\tfrac{1}{2}}.$$​​

Correct option is A

Given:

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}.$$​

Solution:

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

=$$\frac{1}{\frac{3+1}{3}}-\frac{1}{\frac{2+1}{2}}$$

=$$\frac{3}{4} -\frac{2}{3}$$

=$$\frac{9-8}{12}=\frac{1}{12}$$

Option (A) is right.