Find the value of:

​$$(0.63÷1.26)×4+5×3$$​​

Correct option is B

Given:​

​$$(0.63÷1.26)×4+5×3$$

Concept Used:

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$

Solution:

​$$(0.63÷1.26)×4+5×3$$

=$$\frac{0.63}{1.26}×4+5×3$$

=$$\frac{1}{2}×4+5×3$$

= 2 + 15 = 17