Correct option is B
Given:
(0.001)2+(0.022)2+(0.0333)2+(0.04444)2+(0.055555)2(0.01)2+(0.22)2+(0.333)2+(0.4444)2+(0.55555)2
Solution:
(0.001)2+(0.022)2+(0.0333)2+(0.04444)2+(0.055555)2(0.01)2+(0.22)2+(0.333)2+(0.4444)2+(0.55555)2
To make the two terms comparable, we can multiply both the numerator and the denominator by 100100100:
= 100×[(0.001)2+(0.022)2+(0.0333)2+(0.04444)2+(0.055555)2]100×[(0.01)2+(0.22)2+(0.333)2+(0.4444)2+(0.55555)2]
= [(0.01)2+(0.22)2+(0.333)2+(0.4444)2+(0.55555)2]100×[(0.01)2+(0.22)2+(0.333)2+(0.4444)2+(0.55555)2]
= 100
the value of the expression is 100.