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Find the sum of the numbers between 400 and 500 such that when 8, 12, and 16 divides them, it leaves 5 as remainder in each case.
Question

Find the sum of the numbers between 400 and 500 such that when 8, 12, and 16 divides them, it leaves 5 as remainder in each case.

A.

932

B.

922

C.

942

D.

912

Correct option is B

Solution:

Numbers are 8, 12 and 16 that must divide numbers between 400 and 500 and give remainder 5

To find the multiple of different numbers, we need to find out the LCM 

LCM of 8, 12, 16

8 = 2³, 12 = 2² × 3, 16 = 2⁴

LCM = 2⁴ × 3 = 48

Number = 48k + 5

Putting the values of  k possible numbers between 400 and 500 are 

Number = 48 × 9 + 5 = 437

Number = 48 × 10 + 5 = 485

Now,

Sum of numbers = 437 + 485

=> 922

Therefore, option (b) is the correct answer.

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