Find the sum of the cube of the first 6 even numbers.

Correct option is C

​$$\textbf{First 6 even numbers:} \ 2, 4, 6, 8, 10, 12 \\[10pt]\textbf{Cubes of the numbers:} \\2^3 = 8 \\4^3 = 64 \\6^3 = 216 \\8^3 = 512 \\10^3 = 1000 \\12^3 = 1728 \\[10pt]\textbf{Sum of the cubes:} \\8 + 64 + 216 + 512 + 1000 + 1728 = \boxed{3528}$$​​