Find the smallest number that is exactly divisible by each of the numbers 12, 15, 20 and 27.

Correct option is D

Given:
The numbers are 12, 15, 20, and 27.
Formula Used:
The smallest number divisible by all given numbers is their Least Common Multiple (LCM).
Solution:
​$$12 = 2^2 × 3\\15 = 3 × 5\\20 = 2^2 × 5\\27 = 3^3\\$$​​

LCM of 12, 15, 20 and 27 = 2 × 2 × 3 × 3 × 3 × 5 = 540
Alternate Method:
As, the number must be divisible by 27 hence, the answer must be divisible by 9. Only 540 is divisible by 9.