Find the perimeter of a rhombus whose diagonals are of lengths 5 cm and 12 cm.

Correct option is B

Given:

Diagonal 1 ( d₁) = 5 cm
Diagonal 2 (d₂) = 12 cm

Formula used: 

Perimeter of rhombus :
Perimeter = 4 $$\times$$ sides of the rhombus

Solution:

Now, the Pythagorean theorem to find the length of the side of the rhombus:

​$$s^2 = \left(\frac{d_1​}2\right)^2 + \left(\frac{d_2}2\right)^2$$​​

s²= (2.5)² +  (6)²

s² = 6.25 + 36
s =  $$\sqrt{42.25}$$ 

s = 6.5 cm

then, The perimeter of rhombus:

4 $$\times$$​ s = 4 $$\times$$​ 6.5 = 26 cm

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