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    Find the greatest number of 4 digits divisible by 15,25,40 and 75.
    Question

    Find the greatest number of 4 digits divisible by 15,25,40 and 75.

    A.

    9600

    B.

    9400

    C.

    9000

    D.

    9200

    Correct option is A


    Given:
    π‘π‘’π‘šπ‘π‘’π‘Ÿ = 15, 25, 40 π‘Žπ‘›π‘‘ 75
    Solution:
    𝐴𝑠 𝑀𝑒 π‘˜π‘›π‘œπ‘€ π‘‘β„Žπ‘’ π‘”π‘Ÿπ‘’π‘Žπ‘‘π‘’π‘ π‘‘ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ 4 𝑑𝑖𝑔𝑖𝑑𝑠 = 9999
    π‘‡β„Žπ‘’ 𝐿𝐢𝑀 π‘œπ‘“ 15, 25, 40 π‘Žπ‘›π‘‘ 75 = 600
    𝐴𝑠 π‘π‘’π‘Ÿ π‘‘β„Žπ‘’ π‘žπ‘’π‘’π‘ π‘‘π‘–π‘œπ‘› π‘€β„Žπ‘’π‘› 𝑀𝑒 𝑑𝑖𝑣𝑖𝑑𝑒 9999 𝑏𝑦 600 π‘‘β„Žπ‘’π‘› 𝑀𝑒 𝑔𝑒𝑑 16 π‘Žπ‘›π‘‘ π‘Ÿπ‘’π‘šπ‘Žπ‘–π‘›π‘‘π‘’π‘Ÿ 399.
    π‘‡β„Žπ‘’π‘ , π‘‘β„Žπ‘’ π‘”π‘Ÿπ‘’π‘Žπ‘‘π‘’π‘ π‘‘ 4βˆ’π‘‘π‘–π‘”π‘–π‘‘ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘€β„Žπ‘–π‘β„Ž 𝑖𝑠 𝑑𝑖𝑣𝑖𝑑𝑒𝑑 𝑏𝑦 15, 25, 40 π‘Žπ‘›π‘‘ 75 = 9999 – 399 = 9600.
    π‘‡β„Žπ‘’π‘ , π‘‘β„Žπ‘’ π‘π‘œπ‘Ÿπ‘Ÿπ‘’π‘π‘‘ π‘Žπ‘›π‘ π‘€π‘’π‘Ÿ 𝑖𝑠 (π‘Ž).

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