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Find the area of a triangle formed by (1, 0), (-1, 0), (0, 1).
Question

Find the area of a triangle formed by (1, 0), (-1, 0), (0, 1).

A.

1 sq. units

B.

1.5 sq. units

C.

0 sq. units

D.

2 sq. units

Correct option is A

Given:

Vertices of the triangle are:

A(1, 0), B(-1, 0), C(0, 1)

Formula Used:
The area of a triangle with vertices (x1,y1),(x2,y2),(x3,y3)(x_1, y_1), (x_2, y_2), (x_3, y_3)​ is:

Area = 12x1(y2y3)+x2(y3y1)+x3(y1y2)\frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|​​

Solution:

Substitute the coordinates:

Area = 121(01)+(1)(10)+0(00) \frac{1}{2} \left| 1(0 - 1) + (-1)(1 - 0) + 0(0 - 0) \right|​​

=1211+0= \frac{1}{2} \left| -1 - 1 + 0 \right|​​

=12×2= \frac{1}{2} \times |-2|​​

=12×2= \frac{1}{2} \times 2​​

= 1

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