Figure-out the case from the following in which the rope will break if an animal of mass 30 kg climbs on a rope, which can stand a maximum tension of 560 N. Assume g = 10 $$\text{m/s}^2$$​

Correct option is B

​$$\text{Given:} \\\text{Mass of the animal, } m = 30 \, \text{kg} \\\text{Maximum tension in the rope, } T_{\text{max}} = 560 \, \text{N} \\\text{Acceleration due to gravity, } g = 10 \, \text{m/s}^2$$

​$$\text{From the Free Body Diagram (FBD) of the animal:} \\T - mg = ma \\\text{Where:} \\T = \text{Tension in the rope,} \\m = \text{Mass of the animal,} \\g = \text{Gravitational acceleration,} \\a = \text{Acceleration of the animal.} \\T = m(g + a) \\\text{Given that the maximum tension is 560 N, we can substitute it into the equation:} \\T_{\text{max}} = m(g + a) \\560 = 30(10 + a) \\560 = 30(10 + a) \\560 = 300 + 30a \\560 - 300 = 30a \\260 = 30a \\a = \dfrac{260}{30} = 8.67 \, \text{m/s}^2$$​​