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    Evaluate the following expression.[−47÷112]÷[−45×((−2)−(−27))]\left[ \frac{-4}{7} \div \frac{1}{12} \right] \div \left[ -\frac{4}{5} \times \left( (-2
    Question

    Evaluate the following expression.

    [47÷112]÷[45×((2)(27))]\left[ \frac{-4}{7} \div \frac{1}{12} \right] \div \left[ -\frac{4}{5} \times \left( (-2) - \left( -\frac{2}{7} \right) \right) \right]

    A.

    -5

    B.

    15\frac15​​

    C.

    15\frac 15​​

    D.

    5

    Correct option is A

    Given:

    [47÷112]÷[45×((2)(27))]\left[ \frac{-4}{7} \div \frac{1}{12} \right] \div \left[ -\frac{4}{5} \times \left( (-2) - \left( -\frac{2}{7} \right) \right) \right] 

    Formula Used:

    Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​

    Solution:

    [47÷112]÷[45×((2)(27))] =[47×12]÷[45×((2)+27)] =[4×127]÷[45×(147+27)] =[487]÷[45×(127)] =487÷(4835) =487×3548 =5\left[ \frac{-4}{7} \div \frac{1}{12} \right] \div \left[ -\frac{4}{5} \times \left( (-2) - \left( -\frac{2}{7} \right) \right) \right]\\ \ \\= \left[ \frac{-4}{7} \times 12 \right] \div \left[ -\frac{4}{5} \times \left( (-2) + \frac{2}{7} \right) \right]\\ \ \\= \left[ \frac{-4 \times 12}{7} \right] \div \left[ -\frac{4}{5} \times \left( -\frac{14}{7} + \frac{2}{7} \right) \right]\\ \ \\= \left[ \frac{-48}{7} \right] \div \left[ -\frac{4}{5} \times \left( -\frac{12}{7} \right) \right]\\ \ \\= \frac{-48}{7} \div \left( \frac{48}{35} \right)\\ \ \\= \frac{-48}{7} \times \frac{35}{48}\\ \ \\= -5

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