Evaluate: 41 - [36 - {48 ÷ 2 - (6 - 12 ÷ 2) ÷ 3}]

Correct option is A

Given:

​$$41 - [36 - {48 ÷ 2 - (6 - 12 ÷ 2) ÷ 3}]$$

Concept Used:​

​$$\begin{array}{|l|l|}\hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} & [\,], \{\,\}, (\,) \\\hline\text{Orders, of} & ^x \, (\text{power}), \, \sqrt{} \, (\text{root}), \, \text{of} \\\hline\text{Division} & \div \\\hline\text{Multiplication} & \times \\\hline\text{Addition} & + \\\hline\text{Subtraction} & - \\\hline\end{array}$$

Solution:

41 - [36 - {48 ÷ 2 - (6 - 12 ÷ 2) ÷ 3}]

=41 - [36 - {48 ÷ 2 - (6 - 6) ÷ 3}]

=41 - [36 - {48 ÷ 2 - 0 ÷ 3}]

=41- [36 - 24]

= 41 - 12

= 29