Correct option is CGiven: 123+35÷839\frac{1}{\frac{2}{3} + \frac{3}{5}} \div \frac{8}{39}32+531÷398 Solution:123+35÷839\frac{1}{\frac{2}{3} + \frac{3}{5}} \div \frac{8}{39}32+531÷398=12×5+3×315÷839 =1519×398 =15×3919×8 =585152 =3129152= \frac{1}{\frac{2\times 5 + 3\times 3}{15}} \div \frac{8}{39} \\\ \\= \frac{15}{19}\times \frac{39}{8} \\\ \\= \frac{15 \times 39}{19\times 8} \\\ \\= \frac{585}{152} \\\ \\= 3 \frac{129}{152}=152×5+3×31÷398 =1915×839 =19×815×39 =152585 =3152129