Correct option is DGivenZ=x+5ysubject tox+y≥52x−5y≥10x≤2x≥0, y≥0We getNo feasible solution\begin{aligned}&\text{Given} \\&Z = x + 5y \\&\text{subject to} \\&x + y \geq 5 \\&2x - 5y \geq 10 \\&x \leq 2 \\&x \geq 0,\ y \geq 0 \\&\text{We get} \\&\text{No feasible solution}\end{aligned}GivenZ=x+5ysubject tox+y≥52x−5y≥10x≤2x≥0, y≥0We getNo feasible solution