The corner points of the feasible region determined by the system of Linear Constraints are (0, 3), (1, 2) and (3, 0), Let z = px + qy, where p, q > 0, be the objective function. Find the condition on p and q so that the minimum of z occurs at (3, 0) and (1, 2):

Correct option is C

The corner points of the feasible region are (0, 3), (1, 2) and (3, 0).
Also,
z=px+qy
If the minimum of z occurs at (3, 0) and (1, 2), then
p(3)+q(0)=p(1)+q(2)
3p=p+2q
2p=2q
p=q