Correct option is C
The corner points of the feasible region are (0, 3), (1, 2) and (3, 0).
Also,
z=px+qy
If the minimum of z occurs at (3, 0) and (1, 2), then
p(3)+q(0)=p(1)+q(2)
3p=p+2q
2p=2q
p=q
The corner points of the feasible region are (0, 3), (1, 2) and (3, 0).
Also,
z=px+qy
If the minimum of z occurs at (3, 0) and (1, 2), then
p(3)+q(0)=p(1)+q(2)
3p=p+2q
2p=2q
p=q