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    The corner points of the feasible region determined by the system of Linear Constraints are (0, 3), (1, 2) and (3, 0), Let z = px + qy, where p, q &gt
    Question

    The corner points of the feasible region determined by the system of Linear Constraints are (0, 3), (1, 2) and (3, 0), Let z = px + qy, where p, q > 0, be the objective function. Find the condition on p and q so that the minimum of z occurs at (3, 0) and (1, 2):

    A.

    p = 2q

    B.

    p = 3q

    C.

    p = q

    D.

    p=q/2

    Correct option is C

    The corner points of the feasible region are (0, 3), (1, 2) and (3, 0).
    Also,
    z=px+qy
    If the minimum of z occurs at (3, 0) and (1, 2), then
    p(3)+q(0)=p(1)+q(2)
    3p=p+2q
    2p=2q
    p=q

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