Calculate the smallest five-digit number divisible by 9, 11 and 21.
Given:
Numbers: 9, 11, and 21
Solution:
LCM of 9, 11, and 21:
Prime factorization:
9 = 3²
11 = 11
21 = 3 × 7
LCM = Highest powers of all prime factors = 3² × 7 × 11
LCM = 9 × 7 × 11 = 693
To find the smallest five-digit number divisible by 693:
Smallest five-digit number = 10000
Divide 10000 by 693:
10000 ÷ 693 = 14.43 (approximately)
Take the next whole number greater than 14.43, which is 15.
Smallest five-digit number divisible by 693 = 693 × 15 = 10395
English
100 Questions
100 Marks
90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishLet p be the greatest number of 4-digits which when divided by 21, 22, 24 and 28, the remainder in each case is 8. What is the sum of the digits of p?
The least number of five digits which is exactly divisible by 75 is :
Which of the following numbers is divisible by 99?
The greatest number that divides 63, 75 and 93 leaving remainder 3 in each case is:
The least number of five digits which is exactly divisible by 75 is:
Write the largest 5 digit number which when divided by 469 leaves 3 as remainder
The difference between the largest and the smallest 5-digit numbers made of digits 2, 3, 5, 0 and 9
From a four digit number, a number formed by reversing the digits is subtracted. The new number is always divisible by
The sum of the largest and the smallest 5-digit numbers formed by the digits 3, 4, 0, 6, 5 is
Write the smallest 5-digit number using digits 2, 3, 5, 8 and 9 which is divisible by 9
Suggested Test Series
Suggested Test Series
