Banraj's age is three times the age of his son. His daughter's age is 3 years less than his son's age. If 3 years ago, the sum of the ages of these three was 63 years, then find the present age (in years) of Banraj.
Given:
Banraj’s age is 3 times his son
His daughter’s age is 3 years less then son’s age
3 years ago the sum of ages of all three was 63 years
Solution:
Let the age of son be x
Then Banraj’s age will be = 3x
The age of daughter will be = (x-3)
3 years ago the ages were:
Son’s age = x-3
Banraj’s age = 3x -3
Daughter’s age = (x-3)-3= x-6
Sum of ages = (x-3)+(3x-3) + (x-6) = 63
5x-12 = 63
5x= 75
x= 15
Present age of Banraj = 15 3 = 45 years
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