Arrange the following sub-stages of prophase I in meiotic cell division in the correct sequence: (A) Zygotene (B) Leptotene (C) Diplotene (D) Pachytene
Choose the correct answer from the options given below:

Correct option is C

The correct answer is (C) (B), (A), (D), (C)

Explanation:
• Prophase I is the longest phase of Meiosis I and is divided into five sub-stages based on chromosomal behavior.
• Leptotene (B) is the first stage where chromosomes start to condense and become visible.
• Zygotene (A) involves the pairing of homologous chromosomes (synapsis).
• Pachytene (D) is characterized by the appearance of recombination nodules and crossing over between non-sister chromatids.
• Diplotene (C) follows where the synaptonemal complex dissolves, and chiasmata become visible.
• Though not listed, the final stage is Diakinesis.

Information Booster:
• A common mnemonic to remember the order is: 'LeZPaDiDi' (Leptotene, Zygotene, Pachytene, Diplotene, Diakinesis).
• Crossing over occurs specifically during the Pachytene stage, which is the most critical event for genetic variation.

Additional Knowledge:
• (Option A and B): Place Zygotene before Leptotene, which is incorrect as condensation must precede synapsis.
• (Option D): Incorrectly starts with Diplotene, which is near the end of Prophase I.