An urn contains 10 black and 5 white balls. Two balls are drawn from the urn one after the other without replacement. What is the probability that both drawn balls are black?

Correct option is B

GIVEN:
A = A black ball in the first draw
B = A black ball in the second draw
Solution:
Now,
P(A)= $$\frac{10}{15}=\frac{2}3$$​​
P(B/A) =  $$\frac{9}{14}$$​​
Required probability = P(A∩B) = P(A) × P (B/A)
=  $$\frac{2}3× \frac{9}{14}$$​​

= $$\frac{3}7$$​​