Correct option is DGain×Bandwidth=Constant\text{Gain} \times \text{Bandwidth} = \text{Constant}Gain×Bandwidth=ConstantGain×Bandwidth=1 MHz\text{Gain} \times \text{Bandwidth} = 1 \, \text{MHz}Gain×Bandwidth=1MHzGiven that Gain=1,we calculate the frequency(f):\text{Given that Gain} = 1, \text{we calculate the frequency} (f):Given that Gain=1,we calculate the frequency(f):Bandwidth (BW)=f2−f1\text{Bandwidth (BW)} = f_2 - f_1Bandwidth (BW)=f2−f1BW=1 MHzGain\text{BW} = \frac{1 \, \text{MHz}}{\text{Gain}}BW=Gain1MHzBW=1×1031 KHz\text{BW} = \frac{1 \times 10^3}{1} \, \text{KHz}BW=11×103KHzBW=1000 KHz\text{BW} = 1000 \, \text{KHz}BW=1000KHz