Correct option is D
ADFJ → CFHL
EBKM → GDMO

A(1) → C(3) : +2
D(4) → F(6) : +2
F(6) → H(8) : +2
J(10) → L(12) : +2
Pattern: Each letter in ADFJ is shifted by +2 to get CFHL.
EBKM to GDMO
E(5) → G(7) : +2
B(2) → D(4) : +2
K(11) → M(13) : +2
M(13) → O(15) : +2
Apply the same pattern to HLPX
Positions:
H(8) + 2 = J(10)
L(12) + 2 = N(14)
P(16) + 2 = R(18)
X(24) + 2 = Z(26)
So, HLPX → JNRZ