arrow
arrow
arrow
According to Norton’s theorem, the expression for load current. is-
Question

According to Norton’s theorem, the expression for load current. is-

A.

IL=RL×ISCRint+RintI_L = R_L \times \frac{I_{SC}}{R_{int} + R_{int}}​​

B.

IL=ISCRint+RintI_L = \frac{I_{SC}}{R_{int} + R_{int}}​​

C.

IL=ISC×RintRint+RLI_L = I_{SC} \times \frac{R_{int}}{R_{int} + R_L}​​

D.

IL=RintRint+RLI_L = \frac{R_{int}}{R_{int} + R_L}​​

Correct option is C

According to Norton's theorem, the equation for load current:

IL=ISC×RintRint+RLI_L = I_{SC} \times \frac{R_{int}}{R_{int} + R_L}

By Norton’s theorem, any linear circuit consisting of multiple power sources and resistors can be replaced by a constant current source in parallel with a single resistor.

Vth=IN×RNV_{th} = I_N \times R_N, Rth=RNR_{th} = R_N

IN=VthRthI_N = \frac{V_{th}}{R_{th}}, RN=RthR_N = R_{th}​​​

test-prime-package

Access ‘RRB JE Electrical Engineering’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
343k+ students have already unlocked exclusive benefits with Test Prime!
test-prime-package

Access ‘RRB JE Electrical Engineering’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
343k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow