Correct option is CThe side ratio of two similar triangles is always equal. Given, ∆ABC ~ ∆RST ABRS=ACRT=BCST\frac{AB}{RS} = \frac{AC}{RT} = \frac{BC}{ST}RSAB=RTAC=STBCAB6=14\frac{AB}{6} = \frac{1}{4}6AB=41AB=6×14=1.5AB = 6 \times \frac{1}{4} = 1.5AB=6×41=1.5∴AB=1.5\therefore AB = 1.5∴AB=1.5