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A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5 m and 6.0 m respectively below the free surfa
Question

A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5 m and 6.0 m respectively below the free surface. The position of center of pressure below the free surface will be at a distance of;

A.

3.75 m

B.

4.0 m

C.

4.2 m

D.

4.5 m

Correct option is C

h=h+IAyˉh^* = h + \frac{I}{A \bar{y}}
h=3.75+8×(1.5)3128×4.5×3.75h^* = 3.75 + \frac{8 \times \frac{(1.5)^3}{12}}{8 \times 4.5 \times 3.75}
h=3.75+0.45h^* = 3.75 + 0.45 = 4.2 m​​​

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