A vendor has 120 kg rice of one kind, 160 kg of another kind and 210 kg of a third kind. He wants to sell the rice by filling the three kinds of rice in bags of equal capacity. What should be the greatest capacity of such a bag?
Given:
Quantities of rice are 120 kg, 160 kg, and 210 kg.
Formula Used:
HCF = Highest Common Factor of the given quantities.
Solution:
Prime factorization:
120 = 2³ × 3 × 5
160 = 2⁵ × 5
210 = 2 × 3 × 5 × 7
Common prime factors = 2 × 5 = 10
HCF = 10
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