A train passes a station platform in 50 seconds and a man standing on the platform in 34 seconds. If the speed of the train is 29 m/s, what is the length of the platform? (in meters)

Correct option is B

Ans. (b)
Sol. Let the length of the train be L meters and the length of the platform be P meters.
Given:
· Speed of the train = 29 m/s
· Time to pass the man = 34 seconds (train passes the man, so distance traveled = length of the train = L).
· Time to pass the platform = 50 seconds (train passes the platform, so distance traveled = length of the train + length of the platform = L + P).
From the information, we can use the formula: Distance = Speed × Time
1. For the man: L = Speed × Time = 29 m/s × 34 s = 986 meters
So, the length of the train L is 986 meters.
2. For the platform: L + P = Speed × Time = 29 m/s × 50 s = 1450 meters
Now, substitute the value of L (986 meters) into the equation: 986 + P = 1450 P = 1450 - 986 = 464 meters
Thus, the length of the platform is 464 meters.
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