A tradesman allows a discount of 15% on the marked price. How much above the cost price must he mark his goods to gain 19% through the above transaction?

Correct option is A

Given:

Discount offered = 15%

Desired gain = 19%

Formula Used:

MP = $$\frac{CP×(1+ \frac{Profit \ Percentage}{100})}{(1−\frac{Discount \ Percentage}{100})}$$​

Solution: ​

Let the cost price be CP

Let the marked price be MP 

Now, 

MP = $$\frac{CP×(1+\frac{19}{100})}{(1−\frac{15}{100)} ​}$$ 

MP = CP  $$\frac{(\frac{119}{100})}{(\frac{85}{100})}$$ 

$$\frac{MP}{CP} = \frac{119}{85}$$   

Now,  

119 -85 = 34 

= $$\frac{34}{85}$$ $$\times$$100

= 40%

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