A thief started his journey at a speed of 60 km/h. After 30 minutes, police started from the same place but at a speed of 80 km/h. How much time (in hours) will the police take to catch the thief?

Correct option is A

Given:
Thief's initial speed = 60 km/h
Police's speed = 80 km/h
Time elapsed before police starts (T) = 30 minutes = 0.5 hours
Formula Used:
Distance (D) = Speed (V) × Time (T)
Solution:
Let the time take by police to catch the thief is t.

​$$t = \frac{60 \times 0.5}{80 - 60} \\t = \frac{30 }{20 } \\t = \frac{3}{2} \, \text{hr}$$

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