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A survey is to be made with a chain or tape having its true length L and its incorrect length L’. Let the actual volume be V and measured volume be V’

Question

A survey is to be made with a chain or tape having its true length L and its incorrect length L’. Let the actual volume be V and measured volume be V’. Then the correction for volume is given by:

$V = V' \left( \frac{L'}{L} \right)^2 \\$

$V = V' \left( \frac{L}{L'} \right)^3 \\$

$V = V' \left( \frac{L'}{L} \right)^3 \\$

$V = V' \left( \frac{L'}{L} \right)^4 \\$

Solution

Correct option is C

$V = V' \left( \frac{L'}{L} \right)^3 \\\text{V is the actual or true volume} \\\text{V'} \text{ is the measured or computed volume} \\L = \text{true length} \\L' = \text{incorrect length}$

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A survey is to be made with a chain or tape having its true length L and its incorrect length L’. Let the actual volume be V and measured volume be V’. Then the correction for volume is given by:

$V = V' \left( \frac{L'}{L} \right)^2 \\$

$V = V' \left( \frac{L}{L'} \right)^3 \\$

$V = V' \left( \frac{L'}{L} \right)^3 \\$

$V = V' \left( \frac{L'}{L} \right)^4 \\$

Correct option is C

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A survey is to be made with a chain or tape having its true length L and its incorrect length L’. Let the actual volume be V and measured volume be V’. Then the correction for volume is given by:

​V=V′(L′L)2V = V' \left( \frac{L'}{L} \right)^2 \\V=V′(LL′​)2​​

​V=V′(LL′)3V = V' \left( \frac{L}{L'} \right)^3 \\V=V′(L′L​)3​​

​V=V′(L′L)3V = V' \left( \frac{L'}{L} \right)^3 \\V=V′(LL′​)3​​

​V=V′(L′L)4V = V' \left( \frac{L'}{L} \right)^4 \\V=V′(LL′​)4​​

Correct option is C

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$V = V' \left( \frac{L'}{L} \right)^2 \\$

$V = V' \left( \frac{L}{L'} \right)^3 \\$

$V = V' \left( \frac{L'}{L} \right)^3 \\$

$V = V' \left( \frac{L'}{L} \right)^4 \\$