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A sum of ₹4,200 is divided among A, B, C and D such that the share of B is equal to 23\frac{2}{3}32​​ of the share of C and the share of C i
Question

A sum of ₹4,200 is divided among A, B, C and D such that the share of B is equal to 23\frac{2}{3}​ of the share of C and the share of C is equal to 913\frac{9}{13}​ of the share of D. If the ratio of the share of A and B is 8 : 9, then the difference between the shares of B and D will be:

A.

₹860

B.

₹882

C.

₹840

D.

₹924

Correct option is B

Given

B = 23C \frac{2}{3} C​​

C = 913D \frac{9}{13} D​​

A : B = 8 : 9

Total = ₹4200

D – B = ?

Solution:

BC\frac{B}{C} =  23\frac{2}{3} ; CD=913\frac{C}{D} = \frac{9}{13} ; AB=89\frac{A}{B} = \frac{8}{9}

Total parts = 16 + 18 + 27 + 39 = 100 parts

Each part = 4200100=42\frac{4200}{100} = 42​​

B's share = 18×42=75618\times 42 = 756​​

D's share =  39×42=163839 \times 42 = 1638​​

Thus:

D - B = 1638 - 756 = 882

Thus, the correct option is (b) ₹882

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