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    A sum of `12,000.00 deposited at compound interest becomes double at the end of 5 years. At the end of 15 years the sum will be:
    Question

    A sum of `12,000.00 deposited at compound interest becomes double at the end of 5 years. At the end of 15 years the sum will be:

    A.

    1,08.000.00

    B.

    1,20,000.00

    C.

    8 4.000.00

    D.

    96,000.00

    Correct option is D

    Given:

    Amount =12,000.00

    compound interest becomes double = 5 years.

    Solution:

    Let the initial principal amount be P = 12000 .

    It is given that the sum becomes double at the end of 5 years, so:

    2P = P×(1+r)5P \times (1 + r)^5​​

    Simplifying, we get:

    2 = (1+r)5(1 + r)^5​​

    Taking the 5th root of both sides:

    1 + r = 21/52^{1/5}​​

    Now, to find the amount after 15 years, we use the compound interest formula:

    A =P×(1+r)15 P \times (1 + r)^{15}​​

    Substituting the value of 1 + r as21/5 2^{1/5}​ , we get:

    A = 12000×(21/5)1512000 \times (2^{1/5})^{15}​​

    Simplifying the exponents:

    A =12000×23=12000×8 12000 \times 2^3 = 12000 \times 8​ = 96000

    Thus, the sum at the end of 15 years will be 96,000 .

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