Correct option is Aα=(Ns−Nr)×360(Ns×Nr)where,Ns=Number of stator poles or stator teeth.Nr=Number of rotor poles or rotor teeth.Solution:α=(Ns−Nr)×360(Ns×Nr)=(8−6)×360(8×6)=15∘\alpha = \dfrac{(N_s - N_r) \times 360}{(N_s \times N_r)}\text{where,} \\N_s = \text{Number of stator poles or stator teeth.} \\N_r = \text{Number of rotor poles or rotor teeth.}\text{Solution:} \\\alpha = \dfrac{(N_s - N_r) \times 360}{(N_s \times N_r)} \\= \dfrac{(8 - 6) \times 360}{(8 \times 6)} \\= 15^\circα=(Ns×Nr)(Ns−Nr)×360where,Ns=Number of stator poles or stator teeth.Nr=Number of rotor poles or rotor teeth.Solution:α=(Ns×Nr)(Ns−Nr)×360=(8×6)(8−6)×360=15∘