A shunt generator running at 1000 rpm has generated emf as 200 V. If the speed increases to 1200 rpm, the generated emf will be nearly

Correct option is B

​$$\frac{E_1}{E_2} = \frac{N_1}{N_2}$$

$$E_1 = 200 \text{ V}$$, $$N_1 = 1000 \text{ RPM}$$, $$N_2 = 1200 \text{ RPM}$$

$$\frac{200}{E_2} = \frac{1000}{1200}$$

$$E_2 = 240 \text{ V}$$​​​​​