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    A rectangle has 15 cm as its length and 150 cm2cm^2cm2​ as its area. If the area is increased to 1131 \frac{1}{3}131​​ times the original ar
    Question

    A rectangle has 15 cm as its length and 150 cm2cm^2​ as its area. If the area is increased to 1131 \frac{1}{3}​ times the original area by increasing its length only, then the new perimeter is:​

    A.

    70 cm

    B.

    60 cm

    C.

    80 cm

    D.

    50 cm

    Correct option is B

    Given:

    Length of the rectangle (L) = 15 cm

    Area of the rectangle (A) = 150cm2cm^2 

    ​New area = 1131\frac{1}{3} times the original area 

    Formula Used: 

    Area of Rectangle = Length ×\times Breadth

    Perimeter of Rectangle = 2(Length + Breadth)

    Solution:

    A = L × B 

    150 = 15 × B 

    B=15015B = \frac{150}{15}  

    B = 10cm 

    The new area:

    New area = 113×1501 \frac{1}{3} \times 150 

    ​New area = 43×150\frac{4}{3} \times 150 

    ​New area = 200 cm2cm^2 

    The new length (l) using the new area while keeping the same breadth (10 cm)

    200  = l × 10

    l=20010l= \frac{200}{10}  = 20 cm

    The perimeter of the new rectangle:

    Perimeter = 2 × (L + B)

    Perimeter = 2 × (20 + 10) 

    Perimeter = 2 × 30 

    Perimeter = 60cm 

    The new perimeter of the rectangle is 60 cm

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