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A rectangle has 15 cm as its length and 150 cm2cm^2cm2​ as its area. If the area is increased to 1131 \frac{1}{3}131​​ times the original ar
Question

A rectangle has 15 cm as its length and 150 cm2cm^2​ as its area. If the area is increased to 1131 \frac{1}{3}​ times the original area by increasing its length only, then the new perimeter is:​

A.

70 cm

B.

60 cm

C.

80 cm

D.

50 cm

Correct option is B

Given:

Length of the rectangle (L) = 15 cm

Area of the rectangle (A) = 150cm2cm^2 

​New area = 1131\frac{1}{3} times the original area 

Formula Used: 

Area of Rectangle = Length ×\times Breadth

Perimeter of Rectangle = 2(Length + Breadth)

Solution:

A = L × B 

150 = 15 × B 

B=15015B = \frac{150}{15}  

B = 10cm 

The new area:

New area = 113×1501 \frac{1}{3} \times 150 

​New area = 43×150\frac{4}{3} \times 150 

​New area = 200 cm2cm^2 

The new length (l) using the new area while keeping the same breadth (10 cm)

200  = l × 10

l=20010l= \frac{200}{10}  = 20 cm

The perimeter of the new rectangle:

Perimeter = 2 × (L + B)

Perimeter = 2 × (20 + 10) 

Perimeter = 2 × 30 

Perimeter = 60cm 

The new perimeter of the rectangle is 60 cm

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